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LT7200SAVPBF データシート(PDF) 17 Page - Analog Devices |
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LT7200SAVPBF データシート(HTML) 17 Page - Analog Devices |
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17 / 35 page ![]() Data Sheet LT7200S analog.com Rev 0 17 of 35 APPLICATIONS INFORMATION The first page of the data sheet shows a general LT7200S application circuit. External component selection is largely driven by the target current ripple, load requirement, and switching frequency. Component selection typically begins with the selection of the inductor L and resistor RRT. Once the inductor is chosen, select the input capacitor, CIN, and the output capacitor, COUT. Next, select the feedback resistors to set the desired output voltage. Finally, select the remaining optional external components for functions such as external loop compensation, tracking/soft-start, input UVLO, and PGOOD. Programming Switching Frequency Selection of the switching frequency is a trade-off between efficiency and component size. High frequency operation allows the use of smaller inductor and capacitor values. Operation at lower frequencies improves efficiency by reducing internal gate charge losses but requires larger inductance values and/or capacitance to maintain low output ripple voltage. Connecting a resistor, RRT, from the RT pin to SGND programs the switching frequency, f, from 400kHz to 3MHz according to the following formula: f(Hz) = 1e11 RRT(Ω) The internal PLL has a synchronization range of ±30% around its programmed frequency. Therefore, during external clock synchronization be sure that the external clock frequency is within this ±30% range of the RRT programmed frequency. Inductor Selection For a given input voltage, VIN, output voltage, VOUT, the inductor value, L, and operating frequency, f, determine the ripple current: ∆IL = VOUT f x L x (1 − VOUT VIN ) The inductor current ripple decreases with higher inductor value and higher operating frequency. Lower ripple current reduces core losses in the inductor, ESR losses in the output capacitors, and output voltage ripple. Highest efficiency operation is obtained at low frequency with small ripple current. However, achieving this requires a large inductor. There is a trade-off between component size, efficiency, and operating frequency. A reasonable starting point is to choose a ripple current that is about 40% of IOUT(MAX), which is around 5A per channel. Exceeding 60% of IOUT(MAX) is not recommended. Note that the largest ripple current occurs at the highest VIN. To guarantee that ripple current does not exceed a specified maximum, the inductance should be chosen according to: L = VOUT f x ∆IL(MAX) (1 − VOUT VIN(MAX) ) Once the value for L is known, select the type of inductor. Actual core loss is independent of core size for a fixed inductor value, but is very dependent on the inductance selected. As the inductance or frequency increases, core losses decrease. Unfortunately, increased inductance requires more turns of wire leading to increased DCR and copper losses. |
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