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LM2743MTC/NOPB データシート(PDF) 28 Page - Texas Instruments

部品番号 LM2743MTC/NOPB
部品情報  LM2743 2.2-V to 16-V Input, voltage mode, synchronous buck controller with tracking
PDF  44 Pages
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メーカー  TI2 [Texas Instruments]
ホームページ  https://www.ti.com
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LM2743MTC/NOPB データシート(HTML) 28 Page - Texas Instruments

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K =
4.8W
4.8W + 0.6W
= 89%
K =
POUT
POUT + PTOTAL
x 100%
PCAP =
(1.924A)
2 x 24 m:
1
2
IRMS_RIP = IOUT x
D(1 - D)
PCAP =
(IRMS_RIP)
2 x ESR
n
2
28
LM2743
SNVS276I – APRIL 2004 – REVISED FEBRUARY 2019
www.ti.com
Product Folder Links: LM2743
Submit Documentation Feedback
Copyright © 2004–2019, Texas Instruments Incorporated
Typical Applications (continued)
PCND2 = (4A)
2 x 13 mΩ x 1.3 x (1 - 0.364)
(58)
PCND = 98.42 mW + 172 mW = 270.42 mW
(59)
There are few additional losses that are taken into account:
The following equations show IC Operating Loss (PIC).
PIC = IQ_VCC x VCC,
(60)
where IQ-VCC is the typical operating VCC current
PIC= 1.5 mA x 3.3V = 4.95 mW
(61)
The following equations show FET Gate Charging Loss (PGATE).
PGATE = n x VCC x QGS x fSW
(62)
PGATE = 2 x 3.3 V x 3 nC x 300 kHz
(63)
PGATE = 5.94 mW
(64)
The value n is the total number of FETs used and QGS is the typical gate-source charge value, which is 3 nC. For
the FDS6898A the gate charging loss is 5.94 mW.
The following equations show Input Capacitor Loss (PCAP).
where
(65)
(66)
Here n is the number of paralleled capacitors, ESR is the equivalent series resistance of each, and PCAP is the
dissipation in each. So for example if we use only one input capacitor of 24 m
Ω.
(67)
PCAP = 88.8 mW
(68)
The following equation shows Output Inductor Loss (PIND).
PIND = I
2
OUT x DCR
(69)
where DCR is the DC resistance. Therefore, for example
PIND = (4A)
2 x 11 mΩ
(70)
PIND = 176 mW
(71)
The following equations show Total System Efficiency.
PTOTAL = PFET + PIC + PGATE + PCAP + PIND
(72)
(73)
(74)



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