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LTC2926IGN データシート(PDF) 20 Page - Linear Technology |
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LTC2926IGN データシート(HTML) 20 Page - Linear Technology |
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20 / 28 page ![]() LTC2926 20 2926fa Figure 16. Ratiometric Tracking Example NC RTB1 24.9k RTA1 7.68k 2926 F16 LTC2926 S1 FB1 RAMPBUF TRACK1 TRACK2 GND PGTMR VIN RTB2 18.2k RTA2 5.36k FAULT 10k CPGTMR 1 µF CMGATE 0.1 µF MGATE 0.1 µF VCC RAMP VIN STATUS STATUS/PGI ON ON/OFF RSGATE 10k 3.3V VIN SGATE2 10 Ω Q2 IRF7413Z SGATE1 10 Ω D1 RFB1 15.0k RFA1 9.53k S2 FB2 D2 RFB2 15.0k RFA2 5.76k FAULT OUT IN SENSE RX1 100 Ω 1.8V MODULE 3.3V Q1 IRF7413Z 1.8V SLAVE1 OUT IN SENSE RX2 100 Ω 2.5V MODULE 3.3V 2.5V SLAVE2 APPLICATIO S I FOR ATIO Figure 15. Ratiometric Tracking Waveforms from Figure 16 Circuit 500mV/DIV SLAVE2 SLAVE1 5ms/DIV 2926 F15 500mV/DIV 5ms/DIV Ratiometric Tracking Example This example converts the coincident tracking example to the ratiometric tracking profile shown in Figure 15, using two slave supplies and a master ramp signal (not a master ramp supply). The ramp rate of the master signal remains unchanged (Step 1), the minimum load resistance of the slave loads remains unchanged (Step 2), and there is no delay in ratiometric tracking. Only Step 3 of the three-step design procedure needs to be considered. In this example, the ramp rate of the 1.8V slave supply is 60V/s, and the ramp rate of the 2.5V supply is 83.3V/s. Always verify that the chosen ramp rate will allow the supplies to ramp-up completely before RAMPBUF reaches VCC. If the 1.8V slave supply were to ramp up at 50V/s it would only reach 1.65V because the RAMPBUF signal would reach its final value of VCC = 3.3V before the slave supply reached 1.8V. 3. Solve for the tracking resistors that set the desired ramp rate and voltage offset or time delay of the slave supply. From Equation 4: Rk Vs Vs k TB =• ⎛ ⎝⎜ ⎞ ⎠⎟ = 15 0 100 60 25 . ΩΩ Choose RTB = 24.9kΩ. Since no offset or delay is required, Equation 5c applies: ΔV = 0V From Equation 6: R V V k V k V k V TA = +− + 08 08 15 0 08 953 08 24 9 0 . . . . . . . ΩΩ Ω 224 9 761 . . k k Ω Ω = Choose RTA = 7.68kΩ. |
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